113221143341 has 4 divisors (see below), whose sum is σ = 115982634684. Its totient is φ = 110459652000.

The previous prime is 113221143323. The next prime is 113221143367. The reversal of 113221143341 is 143341122311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 143341122311 = 47 ⋅3049811113.

It can be written as a sum of positive squares in 2 ways, for example, as 43549429225 + 69671714116 = 208685^2 + 263954^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113221143341 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 113221143341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113221143941) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1380745610 + ... + 1380745691.

It is an arithmetic number, because the mean of its divisors is an integer number (28995658671).

Almost surely, 2^113221143341 is an apocalyptic number.

It is an amenable number.

113221143341 is a deficient number, since it is larger than the sum of its proper divisors (2761491343).

113221143341 is an equidigital number, since it uses as much as digits as its factorization.

113221143341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2761491342.

The product of its digits is 1728, while the sum is 26.

Adding to 113221143341 its reverse (143341122311), we get a palindrome (256562265652).

The spelling of 113221143341 in words is "one hundred thirteen billion, two hundred twenty-one million, one hundred forty-three thousand, three hundred forty-one".