113222131333 has 4 divisors (see below), whose sum is σ = 113271168780. Its totient is φ = 113173093888.

The previous prime is 113222131291. The next prime is 113222131411. The reversal of 113222131333 is 333131222311.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 333131222311 = 919 ⋅362493169.

It can be written as a sum of positive squares in 2 ways, for example, as 62881580644 + 50340550689 = 250762^2 + 224367^2 .

It is a cyclic number.

It is not a de Polignac number, because 113222131333 - 2⁹ = 113222130821 is a prime.

It is a super-5 number, since 5×113222131333⁵ (a number of 56 digits) contains 55555 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113222131298 and 113222131307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113222131133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24515260 + ... + 24519877.

It is an arithmetic number, because the mean of its divisors is an integer number (28317792195).

Almost surely, 2^113222131333 is an apocalyptic number.

It is an amenable number.

113222131333 is a deficient number, since it is larger than the sum of its proper divisors (49037447).

113222131333 is an equidigital number, since it uses as much as digits as its factorization.

113222131333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49037446.

The product of its digits is 1944, while the sum is 25.

Adding to 113222131333 its reverse (333131222311), we get a palindrome (446353353644).

The spelling of 113222131333 in words is "one hundred thirteen billion, two hundred twenty-two million, one hundred thirty-one thousand, three hundred thirty-three".