Base | Representation |
---|---|
bin | 1010010011000010100001… |
… | …1111110100001101110001 |
3 | 1111002101121111200021002001 |
4 | 2210300220133310031301 |
5 | 2441000343041034413 |
6 | 40025204123054001 |
7 | 2246000666315635 |
oct | 244605037641561 |
9 | 44071544607061 |
10 | 11322213221233 |
11 | 36757a6215092 |
12 | 132a3a2371301 |
13 | 6418ac30aa45 |
14 | 2b1dd88bcdc5 |
15 | 1497b40634dd |
hex | a4c287f4371 |
11322213221233 has 2 divisors, whose sum is σ = 11322213221234. Its totient is φ = 11322213221232.
The previous prime is 11322213221167. The next prime is 11322213221251. The reversal of 11322213221233 is 33212231222311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11311161324849 + 11051896384 = 3363207^2 + 105128^2 .
It is a cyclic number.
It is not a de Polignac number, because 11322213221233 - 217 = 11322213090161 is a prime.
It is not a weakly prime, because it can be changed into another prime (11322213221273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661106610616 + 5661106610617.
It is an arithmetic number, because the mean of its divisors is an integer number (5661106610617).
Almost surely, 211322213221233 is an apocalyptic number.
It is an amenable number.
11322213221233 is a deficient number, since it is larger than the sum of its proper divisors (1).
11322213221233 is an equidigital number, since it uses as much as digits as its factorization.
11322213221233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 28.
Adding to 11322213221233 its reverse (33212231222311), we get a palindrome (44534444443544).
The spelling of 11322213221233 in words is "eleven trillion, three hundred twenty-two billion, two hundred thirteen million, two hundred twenty-one thousand, two hundred thirty-three".
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