Base | Representation |
---|---|
bin | 10000011110011101110… |
… | …101101111111000011001 |
3 | 11000020110200011120020011 |
4 | 100132131311233320121 |
5 | 122022243433332023 |
6 | 2224045312401521 |
7 | 144541402361464 |
oct | 20363565577031 |
9 | 4006420146204 |
10 | 1132224511513 |
11 | 3a71a0246497 |
12 | 1635238462a1 |
13 | 829caca4774 |
14 | 3cb2b1302db |
15 | 1e6b9a3950d |
hex | 1079dd6fe19 |
1132224511513 has 2 divisors, whose sum is σ = 1132224511514. Its totient is φ = 1132224511512.
The previous prime is 1132224511507. The next prime is 1132224511529. The reversal of 1132224511513 is 3151154222311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 900350481424 + 231874030089 = 948868^2 + 481533^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1132224511513 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132224511813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566112255756 + 566112255757.
It is an arithmetic number, because the mean of its divisors is an integer number (566112255757).
Almost surely, 21132224511513 is an apocalyptic number.
It is an amenable number.
1132224511513 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132224511513 is an equidigital number, since it uses as much as digits as its factorization.
1132224511513 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7200, while the sum is 31.
Adding to 1132224511513 its reverse (3151154222311), we get a palindrome (4283378733824).
The spelling of 1132224511513 in words is "one trillion, one hundred thirty-two billion, two hundred twenty-four million, five hundred eleven thousand, five hundred thirteen".
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