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1132254235537 is a prime number
BaseRepresentation
bin10000011110011111100…
…111001000101110010001
311000020112202002200220221
4100132133213020232101
5122022324041014122
62224052253433041
7144542213130445
oct20363747105621
94006482080827
101132254235537
113a7205aa85a7
1216353179b781
1382a041b0c49
143cb3106a825
151e6bc45b6c7
hex1079f9c8b91

1132254235537 has 2 divisors, whose sum is σ = 1132254235538. Its totient is φ = 1132254235536.

The previous prime is 1132254235501. The next prime is 1132254235547. The reversal of 1132254235537 is 7355324522311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1131721502976 + 532732561 = 1063824^2 + 23081^2 .

It is an emirp because it is prime and its reverse (7355324522311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1132254235537 - 219 = 1132253711249 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1132254235493 and 1132254235502.

It is not a weakly prime, because it can be changed into another prime (1132254235547) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566127117768 + 566127117769.

It is an arithmetic number, because the mean of its divisors is an integer number (566127117769).

Almost surely, 21132254235537 is an apocalyptic number.

It is an amenable number.

1132254235537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132254235537 is an equidigital number, since it uses as much as digits as its factorization.

1132254235537 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 756000, while the sum is 43.

Adding to 1132254235537 its reverse (7355324522311), we get a palindrome (8487578757848).

The spelling of 1132254235537 in words is "one trillion, one hundred thirty-two billion, two hundred fifty-four million, two hundred thirty-five thousand, five hundred thirty-seven".