Base | Representation |
---|---|
bin | 10000011110100010100… |
… | …001111111111000111001 |
3 | 11000020200011021101100201 |
4 | 100132202201333320321 |
5 | 122022424111022111 |
6 | 2224101203402201 |
7 | 144543346366222 |
oct | 20364241777071 |
9 | 4006604241321 |
10 | 1132303220281 |
11 | 3a7230715562 |
12 | 163546083361 |
13 | 82a113a21bc |
14 | 3cb3777c249 |
15 | 1e6c18d56c1 |
hex | 107a287fe39 |
1132303220281 has 2 divisors, whose sum is σ = 1132303220282. Its totient is φ = 1132303220280.
The previous prime is 1132303220231. The next prime is 1132303220341. The reversal of 1132303220281 is 1820223032311.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 652636163881 + 479667056400 = 807859^2 + 692580^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1132303220281 is a prime.
It is a super-2 number, since 2×11323032202812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1132303220231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566151610140 + 566151610141.
It is an arithmetic number, because the mean of its divisors is an integer number (566151610141).
Almost surely, 21132303220281 is an apocalyptic number.
It is an amenable number.
1132303220281 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132303220281 is an equidigital number, since it uses as much as digits as its factorization.
1132303220281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 28.
Adding to 1132303220281 its reverse (1820223032311), we get a palindrome (2952526252592).
The spelling of 1132303220281 in words is "one trillion, one hundred thirty-two billion, three hundred three million, two hundred twenty thousand, two hundred eighty-one".
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