Base | Representation |
---|---|
bin | 11001101111101110000101… |
… | …101011001000010101110111 |
3 | 112211220201121211022112010021 |
4 | 121233232011223020111313 |
5 | 104320131443132004120 |
6 | 1040453205134510011 |
7 | 32564426330305135 |
oct | 3157560553102567 |
9 | 484821554275107 |
10 | 113230465500535 |
11 | 33095852954589 |
12 | 108489a5965307 |
13 | 4b24782a7b706 |
14 | 1dd65530d8755 |
15 | d155b6d05aaa |
hex | 66fb85ac8577 |
113230465500535 has 8 divisors (see below), whose sum is σ = 136381675920480. Its totient is φ = 90247627520544.
The previous prime is 113230465500479. The next prime is 113230465500629. The reversal of 113230465500535 is 535005564032311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 113230465500535 - 221 = 113230463403383 is a prime.
It is a super-2 number, since 2×1132304655005352 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113230465500491 and 113230465500500.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42093108507 + ... + 42093111196.
It is an arithmetic number, because the mean of its divisors is an integer number (17047709490060).
Almost surely, 2113230465500535 is an apocalyptic number.
113230465500535 is a deficient number, since it is larger than the sum of its proper divisors (23151210419945).
113230465500535 is an equidigital number, since it uses as much as digits as its factorization.
113230465500535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 84186219977.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 113230465500535 in words is "one hundred thirteen trillion, two hundred thirty billion, four hundred sixty-five million, five hundred thousand, five hundred thirty-five".
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