Base | Representation |
---|---|
bin | 110100101110100010… |
… | …1111111011000011001 |
3 | 101211021021002211122222 |
4 | 1221131011333120121 |
5 | 3323344114013423 |
6 | 124003445153425 |
7 | 11115653425526 |
oct | 1513505773031 |
9 | 354237084588 |
10 | 113231001113 |
11 | 44025a4806a |
12 | 19b409bb875 |
13 | a8a6a01299 |
14 | 56a235c14d |
15 | 2e2aabb3c8 |
hex | 1a5d17f619 |
113231001113 has 2 divisors, whose sum is σ = 113231001114. Its totient is φ = 113231001112.
The previous prime is 113231001089. The next prime is 113231001133. The reversal of 113231001113 is 311100132311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112019404249 + 1211596864 = 334693^2 + 34808^2 .
It is a cyclic number.
It is not a de Polignac number, because 113231001113 - 230 = 112157259289 is a prime.
It is a super-2 number, since 2×1132310011132 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113231001091 and 113231001100.
It is not a weakly prime, because it can be changed into another prime (113231001133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615500556 + 56615500557.
It is an arithmetic number, because the mean of its divisors is an integer number (56615500557).
Almost surely, 2113231001113 is an apocalyptic number.
It is an amenable number.
113231001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231001113 is an equidigital number, since it uses as much as digits as its factorization.
113231001113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113231001113 its reverse (311100132311), we get a palindrome (424331133424).
The spelling of 113231001113 in words is "one hundred thirteen billion, two hundred thirty-one million, one thousand, one hundred thirteen".
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