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113231001113 is a prime number
BaseRepresentation
bin110100101110100010…
…1111111011000011001
3101211021021002211122222
41221131011333120121
53323344114013423
6124003445153425
711115653425526
oct1513505773031
9354237084588
10113231001113
1144025a4806a
1219b409bb875
13a8a6a01299
1456a235c14d
152e2aabb3c8
hex1a5d17f619

113231001113 has 2 divisors, whose sum is σ = 113231001114. Its totient is φ = 113231001112.

The previous prime is 113231001089. The next prime is 113231001133. The reversal of 113231001113 is 311100132311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112019404249 + 1211596864 = 334693^2 + 34808^2 .

It is a cyclic number.

It is not a de Polignac number, because 113231001113 - 230 = 112157259289 is a prime.

It is a super-2 number, since 2×1132310011132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113231001091 and 113231001100.

It is not a weakly prime, because it can be changed into another prime (113231001133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615500556 + 56615500557.

It is an arithmetic number, because the mean of its divisors is an integer number (56615500557).

Almost surely, 2113231001113 is an apocalyptic number.

It is an amenable number.

113231001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

113231001113 is an equidigital number, since it uses as much as digits as its factorization.

113231001113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 113231001113 its reverse (311100132311), we get a palindrome (424331133424).

The spelling of 113231001113 in words is "one hundred thirteen billion, two hundred thirty-one million, one thousand, one hundred thirteen".