11323131030433 has 2 divisors, whose sum is σ = 11323131030434. Its totient is φ = 11323131030432.

The previous prime is 11323131030427. The next prime is 11323131030481. The reversal of 11323131030433 is 33403013132311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7912338900544 + 3410792129889 = 2812888^2 + 1846833^2 .

It is an emirp because it is prime and its reverse (33403013132311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11323131030433 - 2²⁵ = 11323097476001 is a prime.

It is not a weakly prime, because it can be changed into another prime (11323131030413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661565515216 + 5661565515217.

It is an arithmetic number, because the mean of its divisors is an integer number (5661565515217).

Almost surely, 2^{11323131030433} is an apocalyptic number.

It is an amenable number.

11323131030433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323131030433 is an equidigital number, since it uses as much as digits as its factorization.

11323131030433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 28.

Adding to 11323131030433 its reverse (33403013132311), we get a palindrome (44726144162744).

The spelling of 11323131030433 in words is "eleven trillion, three hundred twenty-three billion, one hundred thirty-one million, thirty thousand, four hundred thirty-three".