Base | Representation |
---|---|
bin | 11001101111101110111001… |
… | …010101101101110100110011 |
3 | 112211220210212020100121101002 |
4 | 121233232321111231310303 |
5 | 104320140232032132011 |
6 | 1040453431141232215 |
7 | 32564456654064401 |
oct | 3157567125556463 |
9 | 484823766317332 |
10 | 113231332302131 |
11 | 3309615817143a |
12 | 10848ba810266b |
13 | 4b24890520374 |
14 | 1dd65d6292471 |
15 | d15617e75c3b |
hex | 66fbb956dd33 |
113231332302131 has 2 divisors, whose sum is σ = 113231332302132. Its totient is φ = 113231332302130.
The previous prime is 113231332302047. The next prime is 113231332302139. The reversal of 113231332302131 is 131203233132311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113231332302131 - 210 = 113231332301107 is a prime.
It is a super-2 number, since 2×1132313323021312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113231332302094 and 113231332302103.
It is not a weakly prime, because it can be changed into another prime (113231332302139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56615666151065 + 56615666151066.
It is an arithmetic number, because the mean of its divisors is an integer number (56615666151066).
Almost surely, 2113231332302131 is an apocalyptic number.
113231332302131 is a deficient number, since it is larger than the sum of its proper divisors (1).
113231332302131 is an equidigital number, since it uses as much as digits as its factorization.
113231332302131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 113231332302131 its reverse (131203233132311), we get a palindrome (244434565434442).
The spelling of 113231332302131 in words is "one hundred thirteen trillion, two hundred thirty-one billion, three hundred thirty-two million, three hundred two thousand, one hundred thirty-one".
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