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11323210013147 is a prime number
BaseRepresentation
bin1010010011000110001111…
…1010010001100111011011
31111002111011222022112112002
42210301203322101213123
52441004413230410042
640025451051511215
72246034462025544
oct244614372214733
944074158275462
1011323210013147
11367616794765a
12132a62015850b
13641a0a993946
142b20910334cb
1514982180e132
hexa4c63e919db

11323210013147 has 2 divisors, whose sum is σ = 11323210013148. Its totient is φ = 11323210013146.

The previous prime is 11323210013009. The next prime is 11323210013207. The reversal of 11323210013147 is 74131001232311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11323210013147 - 216 = 11323209947611 is a prime.

It is not a weakly prime, because it can be changed into another prime (11323210015147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661605006573 + 5661605006574.

It is an arithmetic number, because the mean of its divisors is an integer number (5661605006574).

Almost surely, 211323210013147 is an apocalyptic number.

11323210013147 is a deficient number, since it is larger than the sum of its proper divisors (1).

11323210013147 is an equidigital number, since it uses as much as digits as its factorization.

11323210013147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 29.

Adding to 11323210013147 its reverse (74131001232311), we get a palindrome (85454211245458).

The spelling of 11323210013147 in words is "eleven trillion, three hundred twenty-three billion, two hundred ten million, thirteen thousand, one hundred forty-seven".