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113232122110147 is a prime number
BaseRepresentation
bin11001101111101111101000…
…011010100110000011000011
3112211220212220021112000021211
4121233233220122212003003
5104320143341230011042
61040454041353430551
732564515354251565
oct3157575032460303
9484825807460254
10113232122110147
1133096522a80937
121084918870b457
134b249880451a1
141dd666d127335
15d15662488017
hex66fbe86a60c3

113232122110147 has 2 divisors, whose sum is σ = 113232122110148. Its totient is φ = 113232122110146.

The previous prime is 113232122110097. The next prime is 113232122110171. The reversal of 113232122110147 is 741011221232311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113232122110147 is a prime.

It is not a weakly prime, because it can be changed into another prime (113232122110747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616061055073 + 56616061055074.

It is an arithmetic number, because the mean of its divisors is an integer number (56616061055074).

Almost surely, 2113232122110147 is an apocalyptic number.

113232122110147 is a deficient number, since it is larger than the sum of its proper divisors (1).

113232122110147 is an equidigital number, since it uses as much as digits as its factorization.

113232122110147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

Adding to 113232122110147 its reverse (741011221232311), we get a palindrome (854243343342458).

The spelling of 113232122110147 in words is "one hundred thirteen trillion, two hundred thirty-two billion, one hundred twenty-two million, one hundred ten thousand, one hundred forty-seven".