Base | Representation |
---|---|
bin | 11001101111101111101000… |
… | …011010100110000011000011 |
3 | 112211220212220021112000021211 |
4 | 121233233220122212003003 |
5 | 104320143341230011042 |
6 | 1040454041353430551 |
7 | 32564515354251565 |
oct | 3157575032460303 |
9 | 484825807460254 |
10 | 113232122110147 |
11 | 33096522a80937 |
12 | 1084918870b457 |
13 | 4b249880451a1 |
14 | 1dd666d127335 |
15 | d15662488017 |
hex | 66fbe86a60c3 |
113232122110147 has 2 divisors, whose sum is σ = 113232122110148. Its totient is φ = 113232122110146.
The previous prime is 113232122110097. The next prime is 113232122110171. The reversal of 113232122110147 is 741011221232311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113232122110147 is a prime.
It is not a weakly prime, because it can be changed into another prime (113232122110747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616061055073 + 56616061055074.
It is an arithmetic number, because the mean of its divisors is an integer number (56616061055074).
Almost surely, 2113232122110147 is an apocalyptic number.
113232122110147 is a deficient number, since it is larger than the sum of its proper divisors (1).
113232122110147 is an equidigital number, since it uses as much as digits as its factorization.
113232122110147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4032, while the sum is 31.
Adding to 113232122110147 its reverse (741011221232311), we get a palindrome (854243343342458).
The spelling of 113232122110147 in words is "one hundred thirteen trillion, two hundred thirty-two billion, one hundred twenty-two million, one hundred ten thousand, one hundred forty-seven".
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