Base | Representation |
---|---|
bin | 11001101111101111101001… |
… | …100011100010100010110011 |
3 | 112211220212221121111111221222 |
4 | 121233233221203202202303 |
5 | 104320143411123413212 |
6 | 1040454043315335255 |
7 | 32564516005633406 |
oct | 3157575143424263 |
9 | 484825847444858 |
10 | 113232141232307 |
11 | 33096532851679 |
12 | 10849192bb152b |
13 | 4b2498bcabb86 |
14 | 1dd66718a3d3d |
15 | d15663eb3c72 |
hex | 66fbe98e28b3 |
113232141232307 has 2 divisors, whose sum is σ = 113232141232308. Its totient is φ = 113232141232306.
The previous prime is 113232141232303. The next prime is 113232141232321. The reversal of 113232141232307 is 703232141232311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113232141232307 - 22 = 113232141232303 is a prime.
It is not a weakly prime, because it can be changed into another prime (113232141232303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56616070616153 + 56616070616154.
It is an arithmetic number, because the mean of its divisors is an integer number (56616070616154).
Almost surely, 2113232141232307 is an apocalyptic number.
113232141232307 is a deficient number, since it is larger than the sum of its proper divisors (1).
113232141232307 is an equidigital number, since it uses as much as digits as its factorization.
113232141232307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36288, while the sum is 35.
Adding to 113232141232307 its reverse (703232141232311), we get a palindrome (816464282464618).
It can be divided in two parts, 11323214 and 1232307, that added together give a palindrome (12555521).
The spelling of 113232141232307 in words is "one hundred thirteen trillion, two hundred thirty-two billion, one hundred forty-one million, two hundred thirty-two thousand, three hundred seven".
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