Base | Representation |
---|---|
bin | 10000011110100011101… |
… | …010111001111111100011 |
3 | 11000020201111020101120222 |
4 | 100132203222321333203 |
5 | 122022444004121033 |
6 | 2224103125153255 |
7 | 144544001010335 |
oct | 20364352717743 |
9 | 4006644211528 |
10 | 1132322332643 |
11 | 3a72404899a7 |
12 | 16355055b82b |
13 | 82a153345a8 |
14 | 3cb3a115455 |
15 | 1e6c340d598 |
hex | 107a3ab9fe3 |
1132322332643 has 2 divisors, whose sum is σ = 1132322332644. Its totient is φ = 1132322332642.
The previous prime is 1132322332639. The next prime is 1132322332679. The reversal of 1132322332643 is 3462332232311.
It is a weak prime.
It is an emirp because it is prime and its reverse (3462332232311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1132322332643 - 22 = 1132322332639 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132322332613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566161166321 + 566161166322.
It is an arithmetic number, because the mean of its divisors is an integer number (566161166322).
Almost surely, 21132322332643 is an apocalyptic number.
1132322332643 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132322332643 is an equidigital number, since it uses as much as digits as its factorization.
1132322332643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 93312, while the sum is 35.
Adding to 1132322332643 its reverse (3462332232311), we get a palindrome (4594654564954).
The spelling of 1132322332643 in words is "one trillion, one hundred thirty-two billion, three hundred twenty-two million, three hundred thirty-two thousand, six hundred forty-three".
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