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1132331121213 = 3377443707071
BaseRepresentation
bin10000011110100100001…
…100011011101000111101
311000020202002202220020120
4100132210030123220331
5122023003231334323
62224104041405153
7144544135503105
oct20364414335075
94006662686216
101132331121213
113a7245441986
121635534997b9
1382a170c0926
143cb3b362205
151e6c40975e3
hex107a431ba3d

1132331121213 has 4 divisors (see below), whose sum is σ = 1509774828288. Its totient is φ = 754887414140.

The previous prime is 1132331121209. The next prime is 1132331121223. The reversal of 1132331121213 is 3121211332311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1132331121213 - 22 = 1132331121209 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1132331121223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 188721853533 + ... + 188721853538.

It is an arithmetic number, because the mean of its divisors is an integer number (377443707072).

Almost surely, 21132331121213 is an apocalyptic number.

It is an amenable number.

1132331121213 is a deficient number, since it is larger than the sum of its proper divisors (377443707075).

1132331121213 is an equidigital number, since it uses as much as digits as its factorization.

1132331121213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377443707074.

The product of its digits is 648, while the sum is 24.

Adding to 1132331121213 its reverse (3121211332311), we get a palindrome (4253542453524).

The spelling of 1132331121213 in words is "one trillion, one hundred thirty-two billion, three hundred thirty-one million, one hundred twenty-one thousand, two hundred thirteen".

Divisors: 1 3 377443707071 1132331121213