Base | Representation |
---|---|
bin | 1010010011000110101000… |
… | …0000001010101110101111 |
3 | 1111002111110002122020110221 |
4 | 2210301222000022232233 |
5 | 2441010120412033403 |
6 | 40025505142312211 |
7 | 2246040142545121 |
oct | 244615200125657 |
9 | 44074402566427 |
10 | 11323312221103 |
11 | 367620a606a43 |
12 | 132a64a428667 |
13 | 641a25bcb41c |
14 | 2b20a083b211 |
15 | 14982a79cdbd |
hex | a4c6a00abaf |
11323312221103 has 8 divisors (see below), whose sum is σ = 11717526974400. Its totient is φ = 10929347848608.
The previous prime is 11323312221097. The next prime is 11323312221107. The reversal of 11323312221103 is 30112221332311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 11323312221103 - 225 = 11323278666671 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11323312221107) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 62503176 + ... + 62684077.
It is an arithmetic number, because the mean of its divisors is an integer number (1464690871800).
Almost surely, 211323312221103 is an apocalyptic number.
11323312221103 is a deficient number, since it is larger than the sum of its proper divisors (394214753297).
11323312221103 is a wasteful number, since it uses less digits than its factorization.
11323312221103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 125190401.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11323312221103 its reverse (30112221332311), we get a palindrome (41435533553414).
The spelling of 11323312221103 in words is "eleven trillion, three hundred twenty-three billion, three hundred twelve million, two hundred twenty-one thousand, one hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •