Base | Representation |
---|---|
bin | 1010010011000110101100… |
… | …0111110101111100110001 |
3 | 1111002111111101222211111002 |
4 | 2210301223013311330301 |
5 | 2441010140214312403 |
6 | 40025511053131345 |
7 | 2246040461342225 |
oct | 244615307657461 |
9 | 44074441884432 |
10 | 11323331010353 |
11 | 367621a17a64a |
12 | 132a654789b55 |
13 | 641a29a7971b |
14 | 2b20a312c785 |
15 | 14982c260188 |
hex | a4c6b1f5f31 |
11323331010353 has 2 divisors, whose sum is σ = 11323331010354. Its totient is φ = 11323331010352.
The previous prime is 11323331010293. The next prime is 11323331010379. The reversal of 11323331010353 is 35301013332311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6412355901169 + 4910975109184 = 2532263^2 + 2216072^2 .
It is a cyclic number.
It is not a de Polignac number, because 11323331010353 - 28 = 11323331010097 is a prime.
It is not a weakly prime, because it can be changed into another prime (11323331010253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5661665505176 + 5661665505177.
It is an arithmetic number, because the mean of its divisors is an integer number (5661665505177).
Almost surely, 211323331010353 is an apocalyptic number.
It is an amenable number.
11323331010353 is a deficient number, since it is larger than the sum of its proper divisors (1).
11323331010353 is an equidigital number, since it uses as much as digits as its factorization.
11323331010353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 29.
Adding to 11323331010353 its reverse (35301013332311), we get a palindrome (46624344342664).
The spelling of 11323331010353 in words is "eleven trillion, three hundred twenty-three billion, three hundred thirty-one million, ten thousand, three hundred fifty-three".
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