Base | Representation |
---|---|
bin | 10000011110101001110… |
… | …001100101000001010011 |
3 | 11000020222121221110222211 |
4 | 100132221301211001103 |
5 | 122023201213320133 |
6 | 2224121224212551 |
7 | 144546353340634 |
oct | 20365161450123 |
9 | 4006877843884 |
10 | 1132424745043 |
11 | 3a7293278949 |
12 | 16357a90a157 |
13 | 82a30611147 |
14 | 3cb4997388b |
15 | 1e6cc3dcbcd |
hex | 107a9c65053 |
1132424745043 has 2 divisors, whose sum is σ = 1132424745044. Its totient is φ = 1132424745042.
The previous prime is 1132424744989. The next prime is 1132424745059. The reversal of 1132424745043 is 3405474242311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1132424745043 - 221 = 1132422647891 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1132424744987 and 1132424745005.
It is not a weakly prime, because it can be changed into another prime (1132424745743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566212372521 + 566212372522.
It is an arithmetic number, because the mean of its divisors is an integer number (566212372522).
Almost surely, 21132424745043 is an apocalyptic number.
1132424745043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132424745043 is an equidigital number, since it uses as much as digits as its factorization.
1132424745043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 322560, while the sum is 40.
Adding to 1132424745043 its reverse (3405474242311), we get a palindrome (4537898987354).
The spelling of 1132424745043 in words is "one trillion, one hundred thirty-two billion, four hundred twenty-four million, seven hundred forty-five thousand, forty-three".
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