Base | Representation |
---|---|
bin | 11001101111111010001011… |
… | …001000111011110000110101 |
3 | 112211221222010012002010212110 |
4 | 121233322023020323300311 |
5 | 104320340032134220201 |
6 | 1040503152532241233 |
7 | 32565366030505341 |
oct | 3157721310736065 |
9 | 484858105063773 |
10 | 113243442101301 |
11 | 330a03018a7826 |
12 | 1084b407770219 |
13 | 4b25a703499c5 |
14 | 1dd70246d2621 |
15 | d15ac61846d6 |
hex | 66fe8b23bc35 |
113243442101301 has 16 divisors (see below), whose sum is σ = 151323729868800. Its totient is φ = 75329427144048.
The previous prime is 113243442101249. The next prime is 113243442101311. The reversal of 113243442101301 is 103101244342311.
It is not a de Polignac number, because 113243442101301 - 214 = 113243442084917 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (113243442101311) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8127130 + ... + 17103716.
It is an arithmetic number, because the mean of its divisors is an integer number (9457733116800).
Almost surely, 2113243442101301 is an apocalyptic number.
It is an amenable number.
113243442101301 is a deficient number, since it is larger than the sum of its proper divisors (38080287767499).
113243442101301 is an equidigital number, since it uses as much as digits as its factorization.
113243442101301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8985848.
The product of its (nonzero) digits is 6912, while the sum is 30.
Adding to 113243442101301 its reverse (103101244342311), we get a palindrome (216344686443612).
The spelling of 113243442101301 in words is "one hundred thirteen trillion, two hundred forty-three billion, four hundred forty-two million, one hundred one thousand, three hundred one".
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