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11324401112443 is a prime number
BaseRepresentation
bin1010010011001010101011…
…1001111101010101111011
31111002121020222120122120211
42210302222321331111323
52441014333141044233
640030205201131551
72246106134143336
oct244625271752573
944077228518524
1011324401112443
113676719224141
12132a8b3029bb7
13641b6a68ca23
142b21652c761d
1514989118c5cd
hexa4caae7d57b

11324401112443 has 2 divisors, whose sum is σ = 11324401112444. Its totient is φ = 11324401112442.

The previous prime is 11324401112429. The next prime is 11324401112461. The reversal of 11324401112443 is 34421110442311.

It is a weak prime.

It is an emirp because it is prime and its reverse (34421110442311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11324401112443 - 29 = 11324401111931 is a prime.

It is not a weakly prime, because it can be changed into another prime (11324401112413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662200556221 + 5662200556222.

It is an arithmetic number, because the mean of its divisors is an integer number (5662200556222).

Almost surely, 211324401112443 is an apocalyptic number.

11324401112443 is a deficient number, since it is larger than the sum of its proper divisors (1).

11324401112443 is an equidigital number, since it uses as much as digits as its factorization.

11324401112443 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9216, while the sum is 31.

Adding to 11324401112443 its reverse (34421110442311), we get a palindrome (45745511554754).

The spelling of 11324401112443 in words is "eleven trillion, three hundred twenty-four billion, four hundred one million, one hundred twelve thousand, four hundred forty-three".