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11324420331 = 37277036873
BaseRepresentation
bin10101000101111110…
…01111000011101011
31002020012220011021020
422202333033003223
5141143022422311
65111413343523
7550425661500
oct124277170353
932205804236
1011324420331
114891381674
122240637ba3
1310b61c5843
14795ddd4a7
154642c3c06
hex2a2fcf0eb

11324420331 has 12 divisors (see below), whose sum is σ = 17564407272. Its totient is φ = 6471097248.

The previous prime is 11324420309. The next prime is 11324420339. The reversal of 11324420331 is 13302442311.

It is a happy number.

It is not a de Polignac number, because 11324420331 - 27 = 11324420203 is a prime.

It is a super-3 number, since 3×113244203313 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (11324420339) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 38518290 + ... + 38518583.

It is an arithmetic number, because the mean of its divisors is an integer number (1463700606).

Almost surely, 211324420331 is an apocalyptic number.

11324420331 is a deficient number, since it is larger than the sum of its proper divisors (6239986941).

11324420331 is an equidigital number, since it uses as much as digits as its factorization.

11324420331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 77036890 (or 77036883 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 11324420331 its reverse (13302442311), we get a palindrome (24626862642).

The spelling of 11324420331 in words is "eleven billion, three hundred twenty-four million, four hundred twenty thousand, three hundred thirty-one".

Divisors: 1 3 7 21 49 147 77036873 231110619 539258111 1617774333 3774806777 11324420331