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113247004543 = 7110315485711
BaseRepresentation
bin110100101111000001…
…1000010011101111111
3101211022101012220020121
41221132003002131333
53323412213121133
6124005220155411
711116236441001
oct1513603023577
9354271186217
10113247004543
1144033a88742
1219b46238b67
13a8aa11557a
1456a4526371
152e2c1cd02d
hex1a5e0c277f

113247004543 has 8 divisors (see below), whose sum is σ = 115957011456. Its totient is φ = 110567969400.

The previous prime is 113247004477. The next prime is 113247004589. The reversal of 113247004543 is 345400742311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 113247004543 - 217 = 113246873471 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 113247004499 and 113247004508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113247004243) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7735543 + ... + 7750168.

It is an arithmetic number, because the mean of its divisors is an integer number (14494626432).

Almost surely, 2113247004543 is an apocalyptic number.

113247004543 is a deficient number, since it is larger than the sum of its proper divisors (2710006913).

113247004543 is a wasteful number, since it uses less digits than its factorization.

113247004543 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15485885.

The product of its (nonzero) digits is 40320, while the sum is 34.

Adding to 113247004543 its reverse (345400742311), we get a palindrome (458647746854).

The spelling of 113247004543 in words is "one hundred thirteen billion, two hundred forty-seven million, four thousand, five hundred forty-three".

Divisors: 1 71 103 7313 15485711 1099485481 1595028233 113247004543