Base | Representation |
---|---|
bin | 100001110000000… |
… | …1100011101111011 |
3 | 2220221000121222101 |
4 | 1003200030131323 |
5 | 4304410410042 |
6 | 304213404231 |
7 | 40031126413 |
oct | 10340143573 |
9 | 2827017871 |
10 | 1132513147 |
11 | 531301987 |
12 | 277339677 |
13 | 15082582c |
14 | aa5a3643 |
15 | 696596b7 |
hex | 4380c77b |
1132513147 has 2 divisors, whose sum is σ = 1132513148. Its totient is φ = 1132513146.
The previous prime is 1132513141. The next prime is 1132513219. The reversal of 1132513147 is 7413152311.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1132513147 is a prime.
It is not a weakly prime, because it can be changed into another prime (1132513141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566256573 + 566256574.
It is an arithmetic number, because the mean of its divisors is an integer number (566256574).
Almost surely, 21132513147 is an apocalyptic number.
1132513147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1132513147 is an equidigital number, since it uses as much as digits as its factorization.
1132513147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2520, while the sum is 28.
The square root of 1132513147 is about 33652.8326742341. The cubic root of 1132513147 is about 1042.3520321671.
Adding to 1132513147 its reverse (7413152311), we get a palindrome (8545665458).
The spelling of 1132513147 in words is "one billion, one hundred thirty-two million, five hundred thirteen thousand, one hundred forty-seven".
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