Search a number
-
+
113251401323 is a prime number
BaseRepresentation
bin110100101111001001…
…1110011111001101011
3101211022200111021111022
41221132103303321223
53323414324320243
6124005454323055
711116322012414
oct1513623637153
9354280437438
10113251401323
1144036511045
1219b477b948b
13a8aacc4908
1456a4d4c80b
152e2c79ab68
hex1a5e4f3e6b

113251401323 has 2 divisors, whose sum is σ = 113251401324. Its totient is φ = 113251401322.

The previous prime is 113251401313. The next prime is 113251401353. The reversal of 113251401323 is 323104152311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113251401323 - 212 = 113251397227 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113251401292 and 113251401301.

It is not a weakly prime, because it can be changed into another prime (113251401313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56625700661 + 56625700662.

It is an arithmetic number, because the mean of its divisors is an integer number (56625700662).

Almost surely, 2113251401323 is an apocalyptic number.

113251401323 is a deficient number, since it is larger than the sum of its proper divisors (1).

113251401323 is an equidigital number, since it uses as much as digits as its factorization.

113251401323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 113251401323 its reverse (323104152311), we get a palindrome (436355553634).

The spelling of 113251401323 in words is "one hundred thirteen billion, two hundred fifty-one million, four hundred one thousand, three hundred twenty-three".