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113251403 is a prime number
BaseRepresentation
bin1101100000000…
…01010001001011
321220002202201102
412300001101023
5212443021103
615123212015
72543423006
oct660012113
9256082642
10113251403
1158a22501
1231b1700b
131a603285
141108053d
159e20e88
hex6c0144b

113251403 has 2 divisors, whose sum is σ = 113251404. Its totient is φ = 113251402.

The previous prime is 113251393. The next prime is 113251417. The reversal of 113251403 is 304152311.

It is a weak prime.

It is an emirp because it is prime and its reverse (304152311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 113251403 - 24 = 113251387 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (113251483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56625701 + 56625702.

It is an arithmetic number, because the mean of its divisors is an integer number (56625702).

Almost surely, 2113251403 is an apocalyptic number.

113251403 is a deficient number, since it is larger than the sum of its proper divisors (1).

113251403 is an equidigital number, since it uses as much as digits as its factorization.

113251403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360, while the sum is 20.

The square root of 113251403 is about 10641.9642453825. The cubic root of 113251403 is about 483.8170810611.

The spelling of 113251403 in words is "one hundred thirteen million, two hundred fifty-one thousand, four hundred three".