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1132521213041 is a prime number
BaseRepresentation
bin10000011110101111100…
…001100100110001110001
311000021020100110120012122
4100132233201210301301
5122023400412304131
62224134552004025
7144551634322511
oct20365741446161
94007210416178
101132521213041
113a7332777769
121635a7090615
1382a475b90ba
143cb586c5841
151e6d5ae5d7b
hex107af864c71

1132521213041 has 2 divisors, whose sum is σ = 1132521213042. Its totient is φ = 1132521213040.

The previous prime is 1132521212971. The next prime is 1132521213107. The reversal of 1132521213041 is 1403121252311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1104872174641 + 27649038400 = 1051129^2 + 166280^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1132521213041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1132521213041.

It is not a weakly prime, because it can be changed into another prime (1132521213541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566260606520 + 566260606521.

It is an arithmetic number, because the mean of its divisors is an integer number (566260606521).

Almost surely, 21132521213041 is an apocalyptic number.

It is an amenable number.

1132521213041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1132521213041 is an equidigital number, since it uses as much as digits as its factorization.

1132521213041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 1132521213041 its reverse (1403121252311), we get a palindrome (2535642465352).

The spelling of 1132521213041 in words is "one trillion, one hundred thirty-two billion, five hundred twenty-one million, two hundred thirteen thousand, forty-one".