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1132540105054 = 243105112530039
BaseRepresentation
bin10000011110110000101…
…001101001000101011110
311000021021200000101011211
4100132300221221011132
5122023420231330204
62224140504535034
7144552254025331
oct20366051510536
94007250011154
101132540105054
113a73424005a6
121635b148147a
1382a4b4a20c7
143cb5b002618
151e6d75c8804
hex107b0a6915e

1132540105054 has 16 divisors (see below), whose sum is σ = 1739971474560. Its totient is φ = 552574675800.

The previous prime is 1132540105033. The next prime is 1132540105079. The reversal of 1132540105054 is 4505010452311.

It is a super-3 number, since 3×11325401050543 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6174634 + ... + 6355405.

It is an arithmetic number, because the mean of its divisors is an integer number (108748217160).

Almost surely, 21132540105054 is an apocalyptic number.

1132540105054 is a deficient number, since it is larger than the sum of its proper divisors (607431369506).

1132540105054 is a wasteful number, since it uses less digits than its factorization.

1132540105054 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12531135.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 1132540105054 its reverse (4505010452311), we get a palindrome (5637550557365).

The spelling of 1132540105054 in words is "one trillion, one hundred thirty-two billion, five hundred forty million, one hundred five thousand, fifty-four".

Divisors: 1 2 43 86 1051 2102 45193 90386 12530039 25060078 538791677 1077583354 13169070989 26338141978 566270052527 1132540105054