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113254033 is a prime number
BaseRepresentation
bin1101100000000…
…01111010010001
321220002220022211
412300001322101
5212443112113
615123232121
72543433454
oct660017221
9256086284
10113254033
1158a24482
1231b18641
131a604529
141108149b
159e21b3d
hex6c01e91

113254033 has 2 divisors, whose sum is σ = 113254034. Its totient is φ = 113254032.

The previous prime is 113254007. The next prime is 113254061. The reversal of 113254033 is 330452311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86545809 + 26708224 = 9303^2 + 5168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113254033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 113253995 and 113254013.

It is not a weakly prime, because it can be changed into another prime (113254333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56627016 + 56627017.

It is an arithmetic number, because the mean of its divisors is an integer number (56627017).

Almost surely, 2113254033 is an apocalyptic number.

It is an amenable number.

113254033 is a deficient number, since it is larger than the sum of its proper divisors (1).

113254033 is an equidigital number, since it uses as much as digits as its factorization.

113254033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 22.

The square root of 113254033 is about 10642.0878120790. The cubic root of 113254033 is about 483.8208262070.

The spelling of 113254033 in words is "one hundred thirteen million, two hundred fifty-four thousand, thirty-three".