Base | Representation |
---|---|
bin | 110100101111010011… |
… | …0010100110101111011 |
3 | 101211100000121212021022 |
4 | 1221132212110311323 |
5 | 3323422100123333 |
6 | 124010150333055 |
7 | 11116411165544 |
oct | 1513646246573 |
9 | 354300555238 |
10 | 113256254843 |
11 | 44039226616 |
12 | 19b4935a18b |
13 | a8ac003b14 |
14 | 56a58534cb |
15 | 2e2ce08c98 |
hex | 1a5e994d7b |
113256254843 has 2 divisors, whose sum is σ = 113256254844. Its totient is φ = 113256254842.
The previous prime is 113256254833. The next prime is 113256254879. The reversal of 113256254843 is 348452652311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113256254843 - 230 = 112182513019 is a prime.
It is a super-2 number, since 2×1132562548432 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113256254794 and 113256254803.
It is not a weakly prime, because it can be changed into another prime (113256254833) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56628127421 + 56628127422.
It is an arithmetic number, because the mean of its divisors is an integer number (56628127422).
Almost surely, 2113256254843 is an apocalyptic number.
113256254843 is a deficient number, since it is larger than the sum of its proper divisors (1).
113256254843 is an equidigital number, since it uses as much as digits as its factorization.
113256254843 is an evil number, because the sum of its binary digits is even.
The product of its digits is 691200, while the sum is 44.
The spelling of 113256254843 in words is "one hundred thirteen billion, two hundred fifty-six million, two hundred fifty-four thousand, eight hundred forty-three".
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