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11325628173649 is a prime number
BaseRepresentation
bin1010010011001111010000…
…0010110100110101010001
31111002201102111111211010011
42210303310002310311101
52441024341303024044
640030531033234521
72246151424040266
oct244636402646521
944081374454104
1011325628173649
113677198933409
12132ab95b62a41
1364200496a64a
142b224025d26d
15149913c71134
hexa4cf40b4d51

11325628173649 has 2 divisors, whose sum is σ = 11325628173650. Its totient is φ = 11325628173648.

The previous prime is 11325628173637. The next prime is 11325628173667. The reversal of 11325628173649 is 94637182652311.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8698116852049 + 2627511321600 = 2949257^2 + 1620960^2 .

It is a cyclic number.

It is not a de Polignac number, because 11325628173649 - 219 = 11325627649361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11325628173593 and 11325628173602.

It is not a weakly prime, because it can be changed into another prime (11325628173619) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662814086824 + 5662814086825.

It is an arithmetic number, because the mean of its divisors is an integer number (5662814086825).

Almost surely, 211325628173649 is an apocalyptic number.

It is an amenable number.

11325628173649 is a deficient number, since it is larger than the sum of its proper divisors (1).

11325628173649 is an equidigital number, since it uses as much as digits as its factorization.

11325628173649 is an evil number, because the sum of its binary digits is even.

The product of its digits is 13063680, while the sum is 58.

The spelling of 11325628173649 in words is "eleven trillion, three hundred twenty-five billion, six hundred twenty-eight million, one hundred seventy-three thousand, six hundred forty-nine".