Base | Representation |
---|---|
bin | 110100101111010100… |
… | …1010101100010100100 |
3 | 101211100002002221222020 |
4 | 1221132221111202210 |
5 | 3323422300403012 |
6 | 124010215303140 |
7 | 11116420663641 |
oct | 1513651254244 |
9 | 354302087866 |
10 | 113257044132 |
11 | 44039715621 |
12 | 19b4967aab0 |
13 | a8ac21c15b |
14 | 56a59badc8 |
15 | 2e2d012a8c |
hex | 1a5ea558a4 |
113257044132 has 24 divisors (see below), whose sum is σ = 264275221056. Its totient is φ = 37751093088.
The previous prime is 113257044113. The next prime is 113257044137. The reversal of 113257044132 is 231440752311.
It is a junction number, because it is equal to n+sod(n) for n = 113257044093 and 113257044102.
It is not an unprimeable number, because it can be changed into a prime (113257044137) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 264418 + ... + 544454.
It is an arithmetic number, because the mean of its divisors is an integer number (11011467544).
Almost surely, 2113257044132 is an apocalyptic number.
113257044132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
113257044132 is an abundant number, since it is smaller than the sum of its proper divisors (151018176924).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113257044132 is a wasteful number, since it uses less digits than its factorization.
113257044132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313747 (or 313745 counting only the distinct ones).
The product of its (nonzero) digits is 20160, while the sum is 33.
Adding to 113257044132 its reverse (231440752311), we get a palindrome (344697796443).
The spelling of 113257044132 in words is "one hundred thirteen billion, two hundred fifty-seven million, forty-four thousand, one hundred thirty-two".
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