Base | Representation |
---|---|
bin | 10101000110001001… |
… | …01100101001111011 |
3 | 1002020022120220112111 |
4 | 22203010230221323 |
5 | 141143404233113 |
6 | 5111504153151 |
7 | 550444104334 |
oct | 124304545173 |
9 | 32208526474 |
10 | 11325852283 |
11 | 489216a4a9 |
12 | 22410087b7 |
13 | 10b65a7555 |
14 | 79629328b |
15 | 4644a813d |
hex | 2a312ca7b |
11325852283 has 2 divisors, whose sum is σ = 11325852284. Its totient is φ = 11325852282.
The previous prime is 11325852277. The next prime is 11325852313. The reversal of 11325852283 is 38225852311.
11325852283 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (38225852311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11325852283 - 225 = 11292297851 is a prime.
It is not a weakly prime, because it can be changed into another prime (11325852203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5662926141 + 5662926142.
It is an arithmetic number, because the mean of its divisors is an integer number (5662926142).
Almost surely, 211325852283 is an apocalyptic number.
11325852283 is a deficient number, since it is larger than the sum of its proper divisors (1).
11325852283 is an equidigital number, since it uses as much as digits as its factorization.
11325852283 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 115200, while the sum is 40.
The spelling of 11325852283 in words is "eleven billion, three hundred twenty-five million, eight hundred fifty-two thousand, two hundred eighty-three".
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