Base | Representation |
---|---|
bin | 11001110000010110101101… |
… | …100111100110000101101011 |
3 | 112212001220012202201201112211 |
4 | 121300112231213212011223 |
5 | 104321340311321213103 |
6 | 1040525221343145551 |
7 | 32600532300631306 |
oct | 3160265547460553 |
9 | 485056182651484 |
10 | 113274085335403 |
11 | 331022a7139093 |
12 | 10855339ba52b7 |
13 | 4b28914a672a5 |
14 | 1dd86d0339b3d |
15 | d167bb4bb36d |
hex | 6705ad9e616b |
113274085335403 has 2 divisors, whose sum is σ = 113274085335404. Its totient is φ = 113274085335402.
The previous prime is 113274085335347. The next prime is 113274085335449. The reversal of 113274085335403 is 304533580472311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113274085335403 - 217 = 113274085204331 is a prime.
It is not a weakly prime, because it can be changed into another prime (113274085335493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56637042667701 + 56637042667702.
It is an arithmetic number, because the mean of its divisors is an integer number (56637042667702).
Almost surely, 2113274085335403 is an apocalyptic number.
113274085335403 is a deficient number, since it is larger than the sum of its proper divisors (1).
113274085335403 is an equidigital number, since it uses as much as digits as its factorization.
113274085335403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3628800, while the sum is 49.
The spelling of 113274085335403 in words is "one hundred thirteen trillion, two hundred seventy-four billion, eighty-five million, three hundred thirty-five thousand, four hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •