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1133001130130 = 25113300113013
BaseRepresentation
bin10000011111001100001…
…000010100000010010010
311000022110210111212200122
4100133030020110002102
5122030341242131010
62224254334150242
7144566552463632
oct20371410240222
94008423455618
101133001130130
113a7559667561
121636bb952382
1382ac2b5c0cc
143cba23306c2
151e712ce3855
hex107cc214092

1133001130130 has 8 divisors (see below), whose sum is σ = 2039402034252. Its totient is φ = 453200452048.

The previous prime is 1133001130127. The next prime is 1133001130201. The reversal of 1133001130130 is 310311003311.

It can be written as a sum of positive squares in 2 ways, for example, as 1081518881521 + 51482248609 = 1039961^2 + 226897^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1133001130099 and 1133001130108.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56650056497 + ... + 56650056516.

Almost surely, 21133001130130 is an apocalyptic number.

1133001130130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1133001130130 is a deficient number, since it is larger than the sum of its proper divisors (906400904122).

1133001130130 is a wasteful number, since it uses less digits than its factorization.

1133001130130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 113300113020.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1133001130130 its reverse (310311003311), we get a palindrome (1443312133441).

The spelling of 1133001130130 in words is "one trillion, one hundred thirty-three billion, one million, one hundred thirty thousand, one hundred thirty".

Divisors: 1 2 5 10 113300113013 226600226026 566500565065 1133001130130