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113302156531 is a prime number
BaseRepresentation
bin110100110000101010…
…1011011010011110011
3101211110012222220112211
41221201111123103303
53324020323002111
6124014510232551
711120506303654
oct1514125332363
9354405886484
10113302156531
11440621281a3
1219b607b5757
13a8b8685995
1456ab9a152b
152e31e74521
hex1a6155b4f3

113302156531 has 2 divisors, whose sum is σ = 113302156532. Its totient is φ = 113302156530.

The previous prime is 113302156519. The next prime is 113302156547. The reversal of 113302156531 is 135651203311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 113302156531 - 27 = 113302156403 is a prime.

It is a super-3 number, since 3×1133021565313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 113302156493 and 113302156502.

It is not a weakly prime, because it can be changed into another prime (113302156831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56651078265 + 56651078266.

It is an arithmetic number, because the mean of its divisors is an integer number (56651078266).

Almost surely, 2113302156531 is an apocalyptic number.

113302156531 is a deficient number, since it is larger than the sum of its proper divisors (1).

113302156531 is an equidigital number, since it uses as much as digits as its factorization.

113302156531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 31.

Adding to 113302156531 its reverse (135651203311), we get a palindrome (248953359842).

The spelling of 113302156531 in words is "one hundred thirteen billion, three hundred two million, one hundred fifty-six thousand, five hundred thirty-one".