Base | Representation |
---|---|
bin | 1010010011100000101111… |
… | …1000100110010010001111 |
3 | 1111010011112200212110021121 |
4 | 2210320023320212102033 |
5 | 2441114000204104403 |
6 | 40033024550141411 |
7 | 2246405653260361 |
oct | 244701370462217 |
9 | 44104480773247 |
10 | 11330323113103 |
11 | 367918801a965 |
12 | 132ba86351867 |
13 | 6425a2548c27 |
14 | 2b25679d0d31 |
15 | 149adb0193bd |
hex | a4e0be2648f |
11330323113103 has 4 divisors (see below), whose sum is σ = 11379800506840. Its totient is φ = 11280845719368.
The previous prime is 11330323113089. The next prime is 11330323113139. The reversal of 11330323113103 is 30131132303311.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11330323113103 - 25 = 11330323113071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11330323110103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24738696525 + ... + 24738696982.
It is an arithmetic number, because the mean of its divisors is an integer number (2844950126710).
Almost surely, 211330323113103 is an apocalyptic number.
11330323113103 is a deficient number, since it is larger than the sum of its proper divisors (49477393737).
11330323113103 is an equidigital number, since it uses as much as digits as its factorization.
11330323113103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49477393736.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 11330323113103 its reverse (30131132303311), we get a palindrome (41461455416414).
The spelling of 11330323113103 in words is "eleven trillion, three hundred thirty billion, three hundred twenty-three million, one hundred thirteen thousand, one hundred three".
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