Base | Representation |
---|---|
bin | 1010010011100001001011… |
… | …1011100001011111010010 |
3 | 1111010011211221022000012201 |
4 | 2210320102323201133102 |
5 | 2441114220434223102 |
6 | 40033044411513414 |
7 | 2246411620104151 |
oct | 244702273413722 |
9 | 44104757260181 |
10 | 11330441320402 |
11 | 3679238817846 |
12 | 132bab9a5886a |
13 | 6425c0b95b89 |
14 | 2b25795a1598 |
15 | 149ae65b8987 |
hex | a4e12ee17d2 |
11330441320402 has 4 divisors (see below), whose sum is σ = 16995661980606. Its totient is φ = 5665220660200.
The previous prime is 11330441320381. The next prime is 11330441320409. The reversal of 11330441320402 is 20402314403311.
It is a happy number.
11330441320402 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 11302243858161 + 28197462241 = 3361881^2 + 167921^2 .
It is not an unprimeable number, because it can be changed into a prime (11330441320409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2832610330099 + ... + 2832610330102.
Almost surely, 211330441320402 is an apocalyptic number.
11330441320402 is a deficient number, since it is larger than the sum of its proper divisors (5665220660204).
11330441320402 is an equidigital number, since it uses as much as digits as its factorization.
11330441320402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5665220660203.
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 11330441320402 its reverse (20402314403311), we get a palindrome (31732755723713).
The spelling of 11330441320402 in words is "eleven trillion, three hundred thirty billion, four hundred forty-one million, three hundred twenty thousand, four hundred two".
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