1133100000033 has 32 divisors (see below), whose sum is σ = 1648393635840. Its totient is φ = 689961602880.

The previous prime is 1133100000001. The next prime is 1133100000049. The reversal of 1133100000033 is 3300000013311.

It is not a de Polignac number, because 1133100000033 - 2⁵ = 1133100000001 is a prime.

It is a super-3 number, since 3×1133100000033³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1133099999958 and 1133100000021.

It is not an unprimeable number, because it can be changed into a prime (1133100000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2976898 + ... + 3335883.

It is an arithmetic number, because the mean of its divisors is an integer number (51512301120).

Almost surely, 2^{1133100000033} is an apocalyptic number.

It is an amenable number.

1133100000033 is a deficient number, since it is larger than the sum of its proper divisors (515293635807).

1133100000033 is a wasteful number, since it uses less digits than its factorization.

1133100000033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6312917.

The product of its (nonzero) digits is 81, while the sum is 15.

Adding to 1133100000033 its reverse (3300000013311), we get a palindrome (4433100013344).

The spelling of 1133100000033 in words is "one trillion, one hundred thirty-three billion, one hundred million, thirty-three", and thus it is an aban number.