Base | Representation |
---|---|
bin | 11001110000111000010000… |
… | …000101010101100110001011 |
3 | 112212012100011111002202010211 |
4 | 121300320100011111212023 |
5 | 104322433034320201312 |
6 | 1040553535011021551 |
7 | 32603245556225113 |
oct | 3160702005254613 |
9 | 485170144082124 |
10 | 113310097037707 |
11 | 331165a6876029 |
12 | 1086030a29a8b7 |
13 | 4b2c13376478b |
14 | 1dda348d5c043 |
15 | d176c7c903a7 |
hex | 670e1015598b |
113310097037707 has 2 divisors, whose sum is σ = 113310097037708. Its totient is φ = 113310097037706.
The previous prime is 113310097037681. The next prime is 113310097037713. The reversal of 113310097037707 is 707730790013311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 113310097037707 - 215 = 113310097004939 is a prime.
It is not a weakly prime, because it can be changed into another prime (113310097037737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56655048518853 + 56655048518854.
It is an arithmetic number, because the mean of its divisors is an integer number (56655048518854).
Almost surely, 2113310097037707 is an apocalyptic number.
113310097037707 is a deficient number, since it is larger than the sum of its proper divisors (1).
113310097037707 is an equidigital number, since it uses as much as digits as its factorization.
113310097037707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 583443, while the sum is 49.
The spelling of 113310097037707 in words is "one hundred thirteen trillion, three hundred ten billion, ninety-seven million, thirty-seven thousand, seven hundred seven".
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