Base | Representation |
---|---|
bin | 10000011111010010001… |
… | …100111011011001100001 |
3 | 11000022201220012120022112 |
4 | 100133102030323121201 |
5 | 122031043332100413 |
6 | 2224312413445105 |
7 | 144602230420025 |
oct | 20372214733141 |
9 | 4008656176275 |
10 | 1133103003233 |
11 | 3a7601118303 |
12 | 163729aa0795 |
13 | 82b0acaa356 |
14 | 3cbb1a8c385 |
15 | 1e71bc182a8 |
hex | 107d233b661 |
1133103003233 has 2 divisors, whose sum is σ = 1133103003234. Its totient is φ = 1133103003232.
The previous prime is 1133103003169. The next prime is 1133103003251. The reversal of 1133103003233 is 3323003013311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 923661311329 + 209441691904 = 961073^2 + 457648^2 .
It is a cyclic number.
It is not a de Polignac number, because 1133103003233 - 26 = 1133103003169 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1133103003199 and 1133103003208.
It is not a weakly prime, because it can be changed into another prime (1133103003283) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566551501616 + 566551501617.
It is an arithmetic number, because the mean of its divisors is an integer number (566551501617).
Almost surely, 21133103003233 is an apocalyptic number.
It is an amenable number.
1133103003233 is a deficient number, since it is larger than the sum of its proper divisors (1).
1133103003233 is an equidigital number, since it uses as much as digits as its factorization.
1133103003233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 1133103003233 its reverse (3323003013311), we get a palindrome (4456106016544).
The spelling of 1133103003233 in words is "one trillion, one hundred thirty-three billion, one hundred three million, three thousand, two hundred thirty-three".
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