11331031023133 has 4 divisors (see below), whose sum is σ = 11334902235840. Its totient is φ = 11327159810428.

The previous prime is 11331031023119. The next prime is 11331031023209. The reversal of 11331031023133 is 33132013013311.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331031023133 is a prime.

It is a super-2 number, since 2×11331031023133² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11331031023098 and 11331031023107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11331031027133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1935601963 + ... + 1935607816.

It is an arithmetic number, because the mean of its divisors is an integer number (2833725558960).

Almost surely, 2^{11331031023133} is an apocalyptic number.

It is an amenable number.

11331031023133 is a deficient number, since it is larger than the sum of its proper divisors (3871212707).

11331031023133 is an equidigital number, since it uses as much as digits as its factorization.

11331031023133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3871212706.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11331031023133 its reverse (33132013013311), we get a palindrome (44463044036444).

The spelling of 11331031023133 in words is "eleven trillion, three hundred thirty-one billion, thirty-one million, twenty-three thousand, one hundred thirty-three".