11331033210131 has 2 divisors, whose sum is σ = 11331033210132. Its totient is φ = 11331033210130.

The previous prime is 11331033210061. The next prime is 11331033210173. The reversal of 11331033210131 is 13101233013311.

11331033210131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11331033210131 - 2¹⁰ = 11331033209107 is a prime.

It is a super-2 number, since 2×11331033210131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331033210097 and 11331033210106.

It is not a weakly prime, because it can be changed into another prime (11331033210181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665516605065 + 5665516605066.

It is an arithmetic number, because the mean of its divisors is an integer number (5665516605066).

Almost surely, 2^{11331033210131} is an apocalyptic number.

11331033210131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331033210131 is an equidigital number, since it uses as much as digits as its factorization.

11331033210131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 11331033210131 its reverse (13101233013311), we get a palindrome (24432266223442).

The spelling of 11331033210131 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, two hundred ten thousand, one hundred thirty-one".