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11331033210307 is a prime number
BaseRepresentation
bin1010010011100011011000…
…1101011001110111000011
31111010020101012001010112001
42210320312031121313003
52441121424000212212
640033223234044431
72246432365064536
oct244706615316703
944106335033461
1011331033210307
113679511936458
121330044119717
136426866b21a5
142b25d4036a1d
15149b2d533657
hexa4e36359dc3

11331033210307 has 2 divisors, whose sum is σ = 11331033210308. Its totient is φ = 11331033210306.

The previous prime is 11331033210257. The next prime is 11331033210319. The reversal of 11331033210307 is 70301233013311.

It is a strong prime.

It is an emirp because it is prime and its reverse (70301233013311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11331033210307 - 211 = 11331033208259 is a prime.

It is a super-2 number, since 2×113310332103072 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331033210397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665516605153 + 5665516605154.

It is an arithmetic number, because the mean of its divisors is an integer number (5665516605154).

Almost surely, 211331033210307 is an apocalyptic number.

11331033210307 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331033210307 is an equidigital number, since it uses as much as digits as its factorization.

11331033210307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402, while the sum is 28.

Adding to 11331033210307 its reverse (70301233013311), we get a palindrome (81632266223618).

The spelling of 11331033210307 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, two hundred ten thousand, three hundred seven".