11331033313513 has 2 divisors, whose sum is σ = 11331033313514. Its totient is φ = 11331033313512.

The previous prime is 11331033313499. The next prime is 11331033313519. The reversal of 11331033313513 is 31531333013311.

11331033313513 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10772593958569 + 558439354944 = 3282163^2 + 747288^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331033313513 is a prime.

It is a super-2 number, since 2×11331033313513² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11331033313519) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665516656756 + 5665516656757.

It is an arithmetic number, because the mean of its divisors is an integer number (5665516656757).

Almost surely, 2^{11331033313513} is an apocalyptic number.

It is an amenable number.

11331033313513 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331033313513 is an equidigital number, since it uses as much as digits as its factorization.

11331033313513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10935, while the sum is 31.

Adding to 11331033313513 its reverse (31531333013311), we get a palindrome (42862366326824).

The spelling of 11331033313513 in words is "eleven trillion, three hundred thirty-one billion, thirty-three million, three hundred thirteen thousand, five hundred thirteen".