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11331110411041 is a prime number
BaseRepresentation
bin1010010011100011101011…
…0011111001101100100001
31111010020120120022100000111
42210320322303321230201
52441122103231123131
640033235032451321
72246434323221551
oct244707263715441
944106516270014
1011331110411041
113679551475513
121330065b49b41
136426996a23b5
142b26003b1161
15149b351d2ab1
hexa4e3acf9b21

11331110411041 has 2 divisors, whose sum is σ = 11331110411042. Its totient is φ = 11331110411040.

The previous prime is 11331110410979. The next prime is 11331110411053. The reversal of 11331110411041 is 14011401113311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10108584360000 + 1222526051041 = 3179400^2 + 1105679^2 .

It is a cyclic number.

It is not a de Polignac number, because 11331110411041 - 213 = 11331110402849 is a prime.

It is not a weakly prime, because it can be changed into another prime (11331110411141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665555205520 + 5665555205521.

It is an arithmetic number, because the mean of its divisors is an integer number (5665555205521).

Almost surely, 211331110411041 is an apocalyptic number.

It is an amenable number.

11331110411041 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331110411041 is an equidigital number, since it uses as much as digits as its factorization.

11331110411041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

Adding to 11331110411041 its reverse (14011401113311), we get a palindrome (25342511524352).

The spelling of 11331110411041 in words is "eleven trillion, three hundred thirty-one billion, one hundred ten million, four hundred eleven thousand, forty-one".