Base | Representation |
---|---|
bin | 1010010011100011101011… |
… | …1110010001110100111010 |
3 | 1111010020120202102112112122 |
4 | 2210320322332101310322 |
5 | 2441122104430200242 |
6 | 40033235211041242 |
7 | 2246434355311445 |
oct | 244707276216472 |
9 | 44106522375478 |
10 | 11331113131322 |
11 | 3679552a63286 |
12 | 1330066a40222 |
13 | 64269a11562a |
14 | 2b26008bc65c |
15 | 149b3556dad2 |
hex | a4e3af91d3a |
11331113131322 has 4 divisors (see below), whose sum is σ = 16996669696986. Its totient is φ = 5665556565660.
The previous prime is 11331113131307. The next prime is 11331113131369. The reversal of 11331113131322 is 22313131113311.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9709512088081 + 1621601043241 = 3116009^2 + 1273421^2 .
It is a junction number, because it is equal to n+sod(n) for n = 11331113131291 and 11331113131300.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2832778282829 + ... + 2832778282832.
Almost surely, 211331113131322 is an apocalyptic number.
11331113131322 is a deficient number, since it is larger than the sum of its proper divisors (5665556565664).
11331113131322 is an equidigital number, since it uses as much as digits as its factorization.
11331113131322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5665556565663.
The product of its digits is 972, while the sum is 26.
Adding to 11331113131322 its reverse (22313131113311), we get a palindrome (33644244244633).
The spelling of 11331113131322 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirteen million, one hundred thirty-one thousand, three hundred twenty-two".
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