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11331113131322 = 25665556565661
BaseRepresentation
bin1010010011100011101011…
…1110010001110100111010
31111010020120202102112112122
42210320322332101310322
52441122104430200242
640033235211041242
72246434355311445
oct244707276216472
944106522375478
1011331113131322
113679552a63286
121330066a40222
1364269a11562a
142b26008bc65c
15149b3556dad2
hexa4e3af91d3a

11331113131322 has 4 divisors (see below), whose sum is σ = 16996669696986. Its totient is φ = 5665556565660.

The previous prime is 11331113131307. The next prime is 11331113131369. The reversal of 11331113131322 is 22313131113311.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 9709512088081 + 1621601043241 = 3116009^2 + 1273421^2 .

It is a junction number, because it is equal to n+sod(n) for n = 11331113131291 and 11331113131300.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2832778282829 + ... + 2832778282832.

Almost surely, 211331113131322 is an apocalyptic number.

11331113131322 is a deficient number, since it is larger than the sum of its proper divisors (5665556565664).

11331113131322 is an equidigital number, since it uses as much as digits as its factorization.

11331113131322 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5665556565663.

The product of its digits is 972, while the sum is 26.

Adding to 11331113131322 its reverse (22313131113311), we get a palindrome (33644244244633).

The spelling of 11331113131322 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirteen million, one hundred thirty-one thousand, three hundred twenty-two".

Divisors: 1 2 5665556565661 11331113131322