Base | Representation |
---|---|
bin | 10000011111010010101… |
… | …111101011011111001110 |
3 | 11000022202112100101201002 |
4 | 100133102233223133032 |
5 | 122031103200104402 |
6 | 2224313341020302 |
7 | 144602401021304 |
oct | 20372257533716 |
9 | 4008675311632 |
10 | 1133112113102 |
11 | 3a760627a722 |
12 | 163730b54692 |
13 | 82b0cb499c8 |
14 | 3cbb2d80274 |
15 | 1e71c917602 |
hex | 107d2beb7ce |
1133112113102 has 4 divisors (see below), whose sum is σ = 1699668169656. Its totient is φ = 566556056550.
The previous prime is 1133112113047. The next prime is 1133112113129. The reversal of 1133112113102 is 2013112113311.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 283278028274 + ... + 283278028277.
It is an arithmetic number, because the mean of its divisors is an integer number (424917042414).
Almost surely, 21133112113102 is an apocalyptic number.
1133112113102 is a deficient number, since it is larger than the sum of its proper divisors (566556056554).
1133112113102 is an equidigital number, since it uses as much as digits as its factorization.
1133112113102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 566556056553.
The product of its (nonzero) digits is 108, while the sum is 20.
Adding to 1133112113102 its reverse (2013112113311), we get a palindrome (3146224226413).
The spelling of 1133112113102 in words is "one trillion, one hundred thirty-three billion, one hundred twelve million, one hundred thirteen thousand, one hundred two".
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