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11331121201307 = 15175040537757
BaseRepresentation
bin1010010011100011101101…
…1101000100000010011011
31111010020121022121112110222
42210320323131010002123
52441122114011420212
640033240100030255
72246434514022215
oct244707335040233
944106538545428
1011331121201307
113679557575396
12133006969238b
1364269b9ac87b
142b26019bd5b5
15149b36114c72
hexa4e3b74409b

11331121201307 has 4 divisors (see below), whose sum is σ = 11406161739216. Its totient is φ = 11256080663400.

The previous prime is 11331121201297. The next prime is 11331121201319. The reversal of 11331121201307 is 70310212113311.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11331121201307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11331121201327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37520268728 + ... + 37520269029.

It is an arithmetic number, because the mean of its divisors is an integer number (2851540434804).

Almost surely, 211331121201307 is an apocalyptic number.

11331121201307 is a deficient number, since it is larger than the sum of its proper divisors (75040537909).

11331121201307 is an equidigital number, since it uses as much as digits as its factorization.

11331121201307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75040537908.

The product of its (nonzero) digits is 756, while the sum is 26.

Adding to 11331121201307 its reverse (70310212113311), we get a palindrome (81641333314618).

The spelling of 11331121201307 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred seven".

Divisors: 1 151 75040537757 11331121201307