Base | Representation |
---|---|
bin | 1010010011100011101101… |
… | …1101000100000010100111 |
3 | 1111010020121022121112111102 |
4 | 2210320323131010002213 |
5 | 2441122114011420234 |
6 | 40033240100030315 |
7 | 2246434514022233 |
oct | 244707335040247 |
9 | 44106538545442 |
10 | 11331121201319 |
11 | 36795575753a7 |
12 | 133006969239b |
13 | 64269b9ac88a |
14 | 2b26019bd5c3 |
15 | 149b36114c7e |
hex | a4e3b7440a7 |
11331121201319 has 2 divisors, whose sum is σ = 11331121201320. Its totient is φ = 11331121201318.
The previous prime is 11331121201297. The next prime is 11331121201327. The reversal of 11331121201319 is 91310212113311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11331121201319 - 212 = 11331121197223 is a prime.
It is a super-2 number, since 2×113311212013192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11331121201291 and 11331121201300.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11331121201399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560600659 + 5665560600660.
It is an arithmetic number, because the mean of its divisors is an integer number (5665560600660).
Almost surely, 211331121201319 is an apocalyptic number.
11331121201319 is a deficient number, since it is larger than the sum of its proper divisors (1).
11331121201319 is an equidigital number, since it uses as much as digits as its factorization.
11331121201319 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 29.
The spelling of 11331121201319 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •