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11331121201319 is a prime number
BaseRepresentation
bin1010010011100011101101…
…1101000100000010100111
31111010020121022121112111102
42210320323131010002213
52441122114011420234
640033240100030315
72246434514022233
oct244707335040247
944106538545442
1011331121201319
1136795575753a7
12133006969239b
1364269b9ac88a
142b26019bd5c3
15149b36114c7e
hexa4e3b7440a7

11331121201319 has 2 divisors, whose sum is σ = 11331121201320. Its totient is φ = 11331121201318.

The previous prime is 11331121201297. The next prime is 11331121201327. The reversal of 11331121201319 is 91310212113311.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11331121201319 - 212 = 11331121197223 is a prime.

It is a super-2 number, since 2×113311212013192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331121201291 and 11331121201300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331121201399) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560600659 + 5665560600660.

It is an arithmetic number, because the mean of its divisors is an integer number (5665560600660).

Almost surely, 211331121201319 is an apocalyptic number.

11331121201319 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331121201319 is an equidigital number, since it uses as much as digits as its factorization.

11331121201319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 11331121201319 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred nineteen".