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11331121201327 is a prime number
BaseRepresentation
bin1010010011100011101101…
…1101000100000010101111
31111010020121022121112111201
42210320323131010002233
52441122114011420302
640033240100030331
72246434514022244
oct244707335040257
944106538545451
1011331121201327
113679557575404
1213300696923a7
1364269b9ac895
142b26019bd5cb
15149b36114c87
hexa4e3b7440af

11331121201327 has 2 divisors, whose sum is σ = 11331121201328. Its totient is φ = 11331121201326.

The previous prime is 11331121201319. The next prime is 11331121201357. The reversal of 11331121201327 is 72310212113311.

It is a happy number.

11331121201327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11331121201327 - 23 = 11331121201319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11331121201295 and 11331121201304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331121201357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665560600663 + 5665560600664.

It is an arithmetic number, because the mean of its divisors is an integer number (5665560600664).

Almost surely, 211331121201327 is an apocalyptic number.

11331121201327 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331121201327 is an equidigital number, since it uses as much as digits as its factorization.

11331121201327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 11331121201327 its reverse (72310212113311), we get a palindrome (83641333314638).

The spelling of 11331121201327 in words is "eleven trillion, three hundred thirty-one billion, one hundred twenty-one million, two hundred one thousand, three hundred twenty-seven".